If nondisjunction occurs in meiosis II during gametogenesis, what will be the result at the completion of meiosis?
a. All the gametes will be diploid.
b. Two gametes will be n + 1, and two will be n - 1.
c. One gamete will be n + 1, one will be n - 1, and two will be n.
d. There will be three extra gametes.
e. Two of the four gametes will be haploid, and two will be diploid.
Answer is C but I can't figure out why B isn't the right answer.
my textual illustration:
normal cell (| |)
interphase before meiosis (X X), double DNA
meiosis begins, and synapsis happens (XX) so the homologous chromosomes join together
then normal meiosis I where the homologous chromosomes split apart into two separate cells (X) and (X)
then abnormal meiosis II, non-disjunction. (X), (nothing), (X), (nothing)
it looks like two cells are n+1 and two are n-1!
a. All the gametes will be diploid.
b. Two gametes will be n + 1, and two will be n - 1.
c. One gamete will be n + 1, one will be n - 1, and two will be n.
d. There will be three extra gametes.
e. Two of the four gametes will be haploid, and two will be diploid.
Answer is C but I can't figure out why B isn't the right answer.
my textual illustration:
normal cell (| |)
interphase before meiosis (X X), double DNA
meiosis begins, and synapsis happens (XX) so the homologous chromosomes join together
then normal meiosis I where the homologous chromosomes split apart into two separate cells (X) and (X)
then abnormal meiosis II, non-disjunction. (X), (nothing), (X), (nothing)
it looks like two cells are n+1 and two are n-1!
