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Ok so I was working on a buoyancy question and I got stumped.
Here's the question:
A cubical block of wood, 10.0 cm on a side, floats on the interface between oil and water with its lower surface 1.50 cm below the interface. The density of oil is 790 kg/m^3.
(a) What is the gauge pressure at the upper face of the block?
(b) What is the gauge pressure at the lower face of the block?
(c) What is the mass and density of the block?
Answers are:
(a) 116 Pa
(b) 921 Pa
(c) .822 kg/ 822 kg/m^3
Also here's a picture of the problem I'm talking about:
http://www.google.com/search?q=A+cubical+block+of+wood%2C+10.0+cm+on+a+side%2C+floats+on+the+interface+between+oil+and+water+with+its+lower+surface+1.50+cm+below+the+interface.+The+density+of+oil+is+790+kg%2Fm%5E3.&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US
fficial&client=firefox-a
(The first result will take you to a PDF file with the problem. Look at P7.)
Ok so how do I go about doing the second part? I got the first part which was (rho)gh = P. But I dunno how to get the second =(
Edit: Never mind. I just realized I just had to use P = (density(H20)1.5 + density(oil)10)g for the second. And I figured out the third part soon after
Here's the question:
A cubical block of wood, 10.0 cm on a side, floats on the interface between oil and water with its lower surface 1.50 cm below the interface. The density of oil is 790 kg/m^3.
(a) What is the gauge pressure at the upper face of the block?
(b) What is the gauge pressure at the lower face of the block?
(c) What is the mass and density of the block?
Answers are:
(a) 116 Pa
(b) 921 Pa
(c) .822 kg/ 822 kg/m^3
Also here's a picture of the problem I'm talking about:
http://www.google.com/search?q=A+cubical+block+of+wood%2C+10.0+cm+on+a+side%2C+floats+on+the+interface+between+oil+and+water+with+its+lower+surface+1.50+cm+below+the+interface.+The+density+of+oil+is+790+kg%2Fm%5E3.&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US
fficial&client=firefox-a(The first result will take you to a PDF file with the problem. Look at P7.)
Ok so how do I go about doing the second part? I got the first part which was (rho)gh = P. But I dunno how to get the second =(
Edit: Never mind. I just realized I just had to use P = (density(H20)1.5 + density(oil)10)g for the second. And I figured out the third part soon after
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