Oxidation Number question

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coolked

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So I'm going through a dumb phase right now and can't figure out the oxidation numbers for this reaction:

Cu + 2AgNO3 -> Cu(NO3)2 + 2Ag

I know Cu has an oxidation number of 0 in the reactant and Ag has an oxidation number of 0 in the product. So what are the oxidation numbers of AgNO3 and Cu(NO3)2 and how did you get to it?? Thaaaankssss

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The oxidation of Ag is (+1) because NO3 is (-1) and there is no overall charge on AgNO3 therefore the charges cancel out. For Cu(NO3)2, the NO3 is (-1) but you have 2 of them so Cu would have to be (+2) to cancel the charges. Hope that helps
 
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