# physics q

Discussion in 'MCAT Study Question Q&A' started by inaccensa, Aug 17, 2011.

1. ### inaccensa 7+ Year Member

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A 5kg block at 5m/s experiences a net force of 10N in a direction perpendicular to its motion. What is the magnitude of its acceleration?

So, we can just plug the numbers in the formula and get 2m/s, but I really dont understand this concept. Had one of the choices been zero, I would have probably picked that. Ek says that the q doesnt specify the direction in which the force is applied...hmmm ok, but realistically how is it possible. Can somebody please shed some light. I'm thinking of a moving car being pulled up by a crane..would this be the correct analogy?

2. ### indianjatt 7+ Year Member

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They're just trying to trick you with the force going in the parallel direction. Just by knowing that the net force is 10N, you can find the net acceleration, which is F/m. 10N/5kg = 2m/s^2

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