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1) Suppose that a 10-cm^3 cube of mass 21kg is submerged in a container of fluid density 0.2 kg/cm^3. The cube is tied by a string and is buoyed upwards such that the string is pulled taut. The tension in the string would be closest to:
4N
6N
8N
10N
Explanation at the back of the book:
The tension can be found by subtracting the weight from the buoyant force:
T=Vpg-mg=(10 cm^3)(0.2 kg/cm^3)(10m/s^2)-(1kg)(10m/s^2)= 10N
can anyone explain where they got the mass of 1kg from??
2)consider a coin in a container hanging from a massless string. string is cut and coin falls hitting the bottom of the container. in reference to the coin, which of the following quantities would have a positive numeric value?
kinetic energy
potential energy
momentum
impulse
Book explanation:
Kinetic energy requires a positive velocity to have a positive value. potential energy may have a positive value at rest. both momentum and impules require a positive velocity vector to have positive values.
i'm not satisfied with this explanation, it sucks in my opinion. if someone wants to take a stab at it and conceptually explain this better, that'd be oh so sweet. thanks.
4N
6N
8N
10N
Explanation at the back of the book:
The tension can be found by subtracting the weight from the buoyant force:
T=Vpg-mg=(10 cm^3)(0.2 kg/cm^3)(10m/s^2)-(1kg)(10m/s^2)= 10N
can anyone explain where they got the mass of 1kg from??
2)consider a coin in a container hanging from a massless string. string is cut and coin falls hitting the bottom of the container. in reference to the coin, which of the following quantities would have a positive numeric value?
kinetic energy
potential energy
momentum
impulse
Book explanation:
Kinetic energy requires a positive velocity to have a positive value. potential energy may have a positive value at rest. both momentum and impules require a positive velocity vector to have positive values.
i'm not satisfied with this explanation, it sucks in my opinion. if someone wants to take a stab at it and conceptually explain this better, that'd be oh so sweet. thanks.