nicolek817
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- Jun 15, 2020
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Suppose the brown allele for eye color (B) is completely dominant over the blue allele for eye color (b). If two brown-eyed parents produce a child that is blue-eyed, what is the probability that at least one out of the next two children they produce will also have blue eyes?Choose 1 answer:
Choose 1 answer:
(Choice C)C44%
I understand how to get to the correct answer, but my question is: why can I not use the rule of addition to just add probability that the first child has blue eyes (1/4) and the probability the second one does...so, 1/4 + 1/4 = 50%
i.e.. For mutually exclusive events X and Y, the probability (P) that one will occur (X or Y) is P(X)+P(Y)
Choose 1 answer:
(Choice C)C44%
I understand how to get to the correct answer, but my question is: why can I not use the rule of addition to just add probability that the first child has blue eyes (1/4) and the probability the second one does...so, 1/4 + 1/4 = 50%
i.e.. For mutually exclusive events X and Y, the probability (P) that one will occur (X or Y) is P(X)+P(Y)