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rate of reaction


Full Member
10+ Year Member
Apr 6, 2010
  1. Medical Student

    Answer: A

    My question: Why isn't B the answer?


    Full Member
    Apr 25, 2011
      Where did you get this question from?

      From the looks of it, the answer they want takes into account all of the reactants before the slow step (B doesn't count, because it's also a product).

      Edit: after some searching around: you're right. Intermediates don't go into the rate law. Rather, you have to express their concentrations in terms of the reactants that formed them. http://www.science.uwaterloo.ca/~cchieh/cact/c123/ratemech.html

      So k2[BC] needs to have that 'translated'; and its concentration is k1[A2][BC]. Thus the rate law k'[A2][BC][BC]
      Last edited:
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