Reaction Rate Vs Equilibrium Constant, Coefficients, and the lke

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

somuchwater

Full Member
10+ Year Member
Joined
Aug 19, 2013
Messages
53
Reaction score
9
Hi,
Here's my source of confusion.

So we use law of mass action and use coefficients of a reaction to determine the exponents of a reaction. aka.

1 A + 2 B => 3 C + 4 D

==>

[C]^3 * [D]^4
--------------------- = K
[A]^1 * ^2

So how exactly does this mesh with determining if a reaction is first order, zero order, etc.?

Like if my exponents above were

[C]^3 * [D]^4
--------------------- = K
[A]^1 * ^1

then isn't the reaction 2nd order?

If we already have the exponents what is the point of a running a reaction law experiment?

Members don't see this ad.
 
reaction order and equilibrium constant are COMPLETELY separate, not related to one another at all
while eq. constant is derived from reaction stoichiometry, reaction order can only be determined via experiments
 
for an elementary reaction, yes they would correlate but you should still think of them as separate (just go by exponents, don't think about Keq)

aA+bB-->cC K= [C]^c / ([A]^a*^b) rate= k[A]^a*^b

for a non-elementary rxn with the same formula, K is the same but the rate law would be different
 
Top