# Slingshot flight time

Discussion in 'MCAT Study Question Q&A' started by ahhhhck, Sep 25, 2014.

1. ### ahhhhck

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Sep 25, 2014
Why do you start counting flight time of a projectile from a slingshot from the point when the projectile leaves the cable and not when it is released? Is it because the elastic potential energy is not converted to kinetic energy until the cable reaches its equilibrium potential?

Thanks.

3. ### Cawolf 2+ Year Member

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Feb 26, 2013
For simplicity and by convention IMO.

It is as you say that all the energy has not been transferred to the projectile until there is no tension in the spring (slingshot).

So why not start our calculations from the point where we know the energy of the projectile? You can do it however you want, but it is much easier to do as you said.

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4. ### justadream 5+ Year Member

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Apr 29, 2011
That'd be like letting initial time (t0) equal to a point in time in which your arm is in mid-throwing-motion (if you were to throw a ball).

The physics at that point is too complex and would not follow simple projectile motion assumptions/principles.

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5. ### ahhhhck

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Sep 25, 2014
Thank you! I realised what a dumb question that is after I thought about it some more hahaha

Definitely complicated it unnecessarily