SDN members see fewer ads and full resolution images. Join our non-profit community!

Slingshot flight time

Discussion in 'MCAT Study Question Q&A' started by ahhhhck, Sep 25, 2014.

  1. ahhhhck


    Sep 25, 2014
    Why do you start counting flight time of a projectile from a slingshot from the point when the projectile leaves the cable and not when it is released? Is it because the elastic potential energy is not converted to kinetic energy until the cable reaches its equilibrium potential?

  2. SDN Members don't see this ad. About the ads.
  3. Cawolf

    Cawolf 2+ Year Member

    Feb 26, 2013
    For simplicity and by convention IMO.

    It is as you say that all the energy has not been transferred to the projectile until there is no tension in the spring (slingshot).

    So why not start our calculations from the point where we know the energy of the projectile? You can do it however you want, but it is much easier to do as you said.
    ahhhhck likes this.
  4. justadream

    justadream 5+ Year Member

    Apr 29, 2011
    That'd be like letting initial time (t0) equal to a point in time in which your arm is in mid-throwing-motion (if you were to throw a ball).

    The physics at that point is too complex and would not follow simple projectile motion assumptions/principles.
    ahhhhck likes this.
  5. ahhhhck


    Sep 25, 2014
    Thank you! I realised what a dumb question that is after I thought about it some more hahaha

    Definitely complicated it unnecessarily

Share This Page