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It has been several years since i have taken chem and I cant seem to find any information that helps me solve this problem.
What is the ph of a 1.0x10-4M Ca(OH)2 solution.
I realize you will get 2 OH's from the dissociation of the Ca(OH)2 but then you will have to take the -log.
Like this: [OH]= 2 x (1.0x10-4) = 2.0 x 10-4
and THEN [pOH] = -log (2.0x10-4)
Im just confused about the freaking -log part. No calculators of course. Could someone enlighten my ignorance. I simply don't remember how to do -logs in my head.
What is the ph of a 1.0x10-4M Ca(OH)2 solution.
I realize you will get 2 OH's from the dissociation of the Ca(OH)2 but then you will have to take the -log.
Like this: [OH]= 2 x (1.0x10-4) = 2.0 x 10-4
and THEN [pOH] = -log (2.0x10-4)
Im just confused about the freaking -log part. No calculators of course. Could someone enlighten my ignorance. I simply don't remember how to do -logs in my head.