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pfaction

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WTF at this entire chapter.

Given that S2O2 in a 0.5L flask is consumed at a rate of 0.008 moles per second, what is the formation rate of S4O6?

2 S2O3 + I2 -> S4O6 + 2I

VoMpD.png

So the rate here is (1/1)S4O6 = -(1/2)S2O3
Nope. What am I doing wrong?
 

chiddler

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what are your choices and what is the answer? maybe it's that the 0.5 L makes it double in concentration. after all, you're given moles/sec, not molarity/sec.

what you wrote looks correct to me :<
 

pfaction

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You're right, I just noticed the answers are asking for MOLARS per second, wow.

On to the next page, do we need to be able to interpret those Absorbance graphs? Holy ****, what?!
 

chiddler

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You're right, I just noticed the answers are asking for MOLARS per second, wow.

On to the next page, do we need to be able to interpret those Absorbance graphs? Holy ****, what?!

they're like people you hate at first sight. they're not so bad once you get to know them. they are just a different way of showing concentration change over time or abundance of stuff at a given time. because different stuff have different absorbance peaks at different wavelengths.
 
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