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tpr big 5 kinematics equations

Discussion in 'MCAT Discussions' started by puffylover, Jun 7, 2010.

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  1. puffylover

    puffylover 7+ Year Member

    74
    0
    Jan 10, 2008
    can someone list them here? i heard they're helpful but can't find it on the internet.

    thanks!
     
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  3. WhizoMD

    WhizoMD 7+ Year Member

    740
    8
    Jan 5, 2009
    d=1/2(Vf+Vi)t
    Vf=Vi+at
    d=Vit+1/2at^2
    d=Vft-1/2at^2
    Vf^2=Vi^2+2ad
     
  4. watchntv

    watchntv 2+ Year Member

    210
    0
    Dec 3, 2009
    so thats
    1.
    D=.5(vf+Vi)*t

    2.
    Vf=Vi+at

    3.
    D=Vi(T)+.5A T^2

    4.
    d=Vf(t)-1/2a(t^2)

    5.
    Vf^2=Vi^2+2ad

    I couldnt read that t's real well,, and equations 3 and 4 look so similar
     
  5. Melomare17

    Melomare17 2+ Year Member

    814
    4
    May 25, 2011
    when do you use that first one?
     
  6. Buttafuoco

    Buttafuoco

    165
    0
    Mar 9, 2012
    average velocity x time. It's something you might use to really quickly find out how far a ball travels after being dropped. If they want to know how far it falls after say 4 seconds, you know that g = 10m/s^2 therefore it's going 40 m/s after 4 seconds so it travels (40 m/s + 0 m/s)/2 * 4s = 80m
     
  7. Melomare17

    Melomare17 2+ Year Member

    814
    4
    May 25, 2011
    oh awesome--does it only apply to if something is just dropped? what if it's thrown can you use it for that?
     
  8. Buttafuoco

    Buttafuoco

    165
    0
    Mar 9, 2012
    Any time where it's easy to figure out the average velocity basically. Like maybe the mcat takes mercy on you and gives you some question where it gives you initial and final velocity of a car, or i guess if you throw something in the air at 30m/s and how far does it travel in the first 2 seconds you'd know it was going 10 m/s after 2s so (10m/s + 30m/s)/2 *2s = 40m.
     
  9. typicalindian

    typicalindian 5+ Year Member

    2,345
    10
    Dec 25, 2010
    Use it for constant linear acceleration I beleive.
     

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