tpr big 5 kinematics equations

[puffylover]

can someone list them here? i heard they're helpful but can't find it on the internet.

thanks!

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[WhizoMD]

d=1/2(Vf+Vi)t
Vf=Vi+at
d=Vit+1/2at^2
d=Vft-1/2at^2
Vf^2=Vi^2+2ad

 

[watchntv]

d=1/2(Vf+Vi)t
Vf=Vi+at
d=Vit+1/2at^2
d=Vft-1/2at^2
Vf^2=Vi^2+2ad

so thats
1.
D=.5(vf+Vi)*t

2.
Vf=Vi+at

3.
D=Vi(T)+.5A T^2

4.
d=Vf(t)-1/2a(t^2)

5.
Vf^2=Vi^2+2ad

I couldnt read that t's real well,, and equations 3 and 4 look so similar

 

[Erythropoietin]

http://en.wikipedia.org/wiki/Linear_motion

 

[Melomare17]

so thats
1.
D=.5(vf+Vi)*t

2.
Vf=Vi+at

3.
D=Vi(T)+.5A T^2

4.
d=Vf(t)-1/2a(t^2)

5.
Vf^2=Vi^2+2ad

I couldnt read that t's real well,, and equations 3 and 4 look so similar

when do you use that first one?

 

[Buttafuoco]

average velocity x time. It's something you might use to really quickly find out how far a ball travels after being dropped. If they want to know how far it falls after say 4 seconds, you know that g = 10m/s^2 therefore it's going 40 m/s after 4 seconds so it travels (40 m/s + 0 m/s)/2 * 4s = 80m

 

[Melomare17]

average velocity x time. It's something you might use to really quickly find out how far a ball travels after being dropped. If they want to know how far it falls after say 4 seconds, you know that g = 10m/s^2 therefore it's going 40 m/s after 4 seconds so it travels (40 m/s + 0 m/s)/2 * 4s = 80m

oh awesome--does it only apply to if something is just dropped? what if it's thrown can you use it for that?

 

[Buttafuoco]

Any time where it's easy to figure out the average velocity basically. Like maybe the mcat takes mercy on you and gives you some question where it gives you initial and final velocity of a car, or i guess if you throw something in the air at 30m/s and how far does it travel in the first 2 seconds you'd know it was going 10 m/s after 2s so (10m/s + 30m/s)/2 *2s = 40m.

 

[typicalindian]

oh awesome--does it only apply to if something is just dropped? what if it's thrown can you use it for that?

Use it for constant linear acceleration I beleive.