Clarification ...
you seem to think that ammonia has a vapor pressure of 760 (atmospheric) @ room temp (25 C).
what you've probably done is taken the specific example of water and applied it to ammonia. Each chemical compound has a unique liq/vap equilibrium behavior, meaning at different temperatures they have different vapor pressures.
So for water it is correct to say @ 25C water will be at VLE when P = 760 mmHg.
But for ammonia that is different.
As for your question:
Assume that both ammonia and water are at the same temperature 25 C, seeing that ammonia is a vapor at RT and water is a liquid at RT, that must mean that the vapor pressure of ammonia is higher than that of waters', which happens to be atmospheric.
Another way to think about it is that more pressure must be applied to the gaseous ammonia @ 25 C in order for you to achieve a liquid state.