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Why is the second product more favored than the other?
Why is the second product more favored than the other?
Why is the second product more favored than the other?
Why is the second product more favored than the other?
hey guys, The H+/H2o in here is use to protonate the OH group on the reactant. after protonated, the OH becomes H2O, which is a good leaving group. the substrate will leave, leaving back a carbocation, the reason why the bottom picture is the major product is because the carbocation that i was left behind is most stable because of markovnikov rule i think
its either markonikov or zaitsev
the propyl group on the right side of the minor product is less favored because it is bulky and it's interfering more with ethyl group below it. While in the major product you have equal groups leading to less hindrance. I think!
I thought thermodynamic/kinetic product was more relevant when it comes to an addition reaction. Plus if heat is applied, you should get more thermodynamic product than kinetic, cz usually thermodynamic products have lower energy as product but higher transition statw energy.I miss ochem now that my DAT is done.
It's probably something like the heat makes the kinetic product form faster than the thermodynamic one. Ask chad on his forum if you're using his videos, he's really helpful, even on stuff not from the website and he gets back to you in 1-2 days (usually).
I thought thermodynamic/kinetic product was more relevant when it comes to an addition reaction. Plus if heat is applied, you should get more thermodynamic product than kinetic, cz usually thermodynamic products have lower energy as product but higher transition statw energy.
Nah, this doesn't make sense. If you look at where the double bond is formed in elimination, the major product is formed from this bulkier propyl chain while the minor product is formed from a smaller ethyl chain. So there are more sterics involved in forming the major product.