Jul 9, 2011
313
1
Status
Medical Student
I'm quite confused about this point.

BR gives this formula on page 186 of their physics book:

V= (V of resistors)+ (V of capacitor)
V=IR+(q/C)

And considering, in this case, V=IR=emf
and (q/C)=V=emf when the capacitor is fully charged.


So when the capacitor is fully charged:

V=emf+emf=2emf


Seems strange, but wondering if this was correct.
 
OP
H
Jul 9, 2011
313
1
Status
Medical Student
Oh wow, nevermind


When capacitor is fully charged,

V=IR+(q/C)

IR=0 because there is no more current through the circuit. so V=(q/C)