Usually, if you use LiAlH4 to reduce any carboxylic acid derivative, you will get its respective alcohol. However, one exception is for amides because when you try to reduce the amide using LAH, the NH2 is a horrible leaving group, and it can't leave. Thus, the OH leaves instead and you form an amine.
This site uses cookies to help personalize content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies and terms of service.
