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Can someone show me the complete steps in rearranging
Y=(F/A)/(ΔL/L)
to
ΔL= (FL)/(AY)
Thank you
Y=(F/A)/(ΔL/L)
to
ΔL= (FL)/(AY)
Thank you
Young's Modulus Algebra
- Thread starter Maverick56
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First, we can simplify y=F/A/deltaL/L as
Y=F*L/A*deltaL
Because delta L is in the denominator and we want to solve for it, reciprocate both sides of the equation. This gives 1/Y = A*deltaL/F*L
Now we want to isolate deltaL. Begin by multiplying each side by F*L, this gives: F*L/y = A*deltaL
To arrive at the final equation, divide by A.
Y=F*L/A*deltaL
Because delta L is in the denominator and we want to solve for it, reciprocate both sides of the equation. This gives 1/Y = A*deltaL/F*L
Now we want to isolate deltaL. Begin by multiplying each side by F*L, this gives: F*L/y = A*deltaL
To arrive at the final equation, divide by A.
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