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  1. F

    gibbs free energy at equilibrium

    On a practice test I encountered a solution to a question that stated: "At EQ, G = zero"... But I believe this is wrong... Isn't EQ the point at which dG is at its lowest (and the pt at which S is at its highest)? By virtue of the equation, dG = -RTlnK, dG is only equal to zero when K = 1...