2011 DAT #183 Biology

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pandalove89

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Consider a somatic cell undergoing mitosis. At anaphase the chromosome number is:

a) N
b) 2N
c) 4N
d) 6N
e) 3N


I thought it would be N since the original 2N would be split but the answer is c) 4N. Why?
 
It is because during anaphase, the paired chromosomes separate but are still in one cell, thus you have twice the number of chromosomes 2*2n
 
It is because during anaphase, the paired chromosomes separate but are still in one cell, thus you have twice the number of chromosomes 2*2n

exactly! plus dont forget that when chromosome consisting of sister chromatids separate in mitosis each chromatid becomes individual chromosomes
 
Wait that confused me even more. how can you have twice the number of chromosomes when splitting during anaphase?

Could someone tell me the number of chromosomes in terms of N during each phase of mitosis and meiosis?

I'm getting really confused.
 
Wait that confused me even more. how can you have twice the number of chromosomes when splitting during anaphase?

Could someone tell me the number of chromosomes in terms of N during each phase of mitosis and meiosis?

I'm getting really confused.

You should look at a bio book for pics/diagrams. You'd probably understand it better by looking at pics rather than reading words trying to describe a picture/scenario.
 
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