2013 Destroyer OChem #228

[Moka11]

---

Members don't see this ad.

The question shows a NMR Spectrum and the answer says that choice B best reflects the picture shown. But the answer explanation seems to be off from the pic.


I found a NMR of what that compound "should" look like, and its not the same thing..

http://www.hmdb.ca/spectra/nmr_one_d/1760

Mistake?

 

[paymaant]

The question shows a NMR Spectrum and the answer says that choice B best reflects the picture shown. But the answer explanation seems to be off from the pic.


I found a NMR of what that compound "should" look like, and its not the same thing..

http://www.hmdb.ca/spectra/nmr_one_d/1760

Mistake?

I do not think it is a mistake. We have to select an answer choice that gives 4 distinct proton signals (C and E). E is not correct because of the acidic proton on the COOH. Therefore, C is your answer. 🙂

 

[Moka11]

I do not think it is a mistake. We have to select an answer choice that gives 4 distinct proton signals (C and E). E is not correct because of the acidic proton on the COOH. Therefore, C is your answer. 🙂

For 228 in Destroyer 2013 the answer is B (and there is only 1 distinct signal at 2.4, at least in my book)

 

[paymaant]

For 228 in Destroyer 2013 the answer is B (and there is only 1 distinct signal at 2.4, at least in my book)

I apologize, I meant to say B as the correct answer! There are 4 signals.

1) alcohol Proton
2) Aromatic Proton (2 equivalent)
3) Aromatic Proton (2 more equivalent)
4) Methyl protons

 

[Moka11]

I apologize, I meant to say B as the correct answer! There are 4 signals.

1) alcohol Proton
2) Aromatic Proton (2 equivalent)
3) Aromatic Proton (2 more equivalent)
4) Methyl protons

Just confirmed with a friend....I have a misprint in mine. 😕

 

[Dotoday]

Yes. The correct answer is B. There is no peak for aldehyde or carboxy acid. There is no triplet or quartet. The only choice is B

Sent from my SPH-L710 using Tapatalk