AAMC Physics Diagnostic # 52 (Open/Closed Pipe Harmonics)

[ihatebluescrubs]

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Discrete Question is here

Hi All,

For this problem, I understand the concept of the half open pipe being wavelength=(4L/n) with n being the harmonic. (Also, I think I know that for this half open pipe, there is only harmonics at n=1,3,5...odds only)

So this problem gives us only 2 wavelengths but doesn't tell us the associated harmonic of such wavelength. I don't get how this question can assume that both wavelengths are one apart from the other (when they substituted the n for both as n and n+2). Couldn't they have been 2 or 3 harmonics apart?

 

[sazerac]

Reread the first word of the question.

 

[Captain Sisko]

do we have to know that equation? they give it to you in the discrete but will that hold for the exam?

Also OP, as sazerac (isn't that a whiskey drink?) brusquely put it - you need to assume that it's n and n+2 because they're consecutive, per the stem. That was a fun one!