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Hello everyone..I would really appreciate it if someone could answer this question for me.
A projectile is fired with an initial velocity v0 at an angle θ above the horizontal. If the effects of air resistance are taken into account, then the projectile will take:
less time to reach its peak than it does to descend from its peak
In the solution, it said that "Since air friction always opposes the direction of the projectile’s velocity, the projectile has a greater downward (negative) acceleration on the way up to its peak (the downward force of air resistance adds to the downward force of gravity as it rises) than on its way down from its peak (the downward force of gravity is opposed by upward force of air resistance). Since the vertical distance covered is the same up as down, a greater acceleration on the way up implies a shorter time to rise than to fall."
This doesn't make sense intuitively though. If air resistance and gravity are both opposing the projectile, then shouldn't it slow down, taking longer to reach the peak?
Thanks!
A projectile is fired with an initial velocity v0 at an angle θ above the horizontal. If the effects of air resistance are taken into account, then the projectile will take:
less time to reach its peak than it does to descend from its peak
In the solution, it said that "Since air friction always opposes the direction of the projectile’s velocity, the projectile has a greater downward (negative) acceleration on the way up to its peak (the downward force of air resistance adds to the downward force of gravity as it rises) than on its way down from its peak (the downward force of gravity is opposed by upward force of air resistance). Since the vertical distance covered is the same up as down, a greater acceleration on the way up implies a shorter time to rise than to fall."
This doesn't make sense intuitively though. If air resistance and gravity are both opposing the projectile, then shouldn't it slow down, taking longer to reach the peak?
Thanks!