MedPR Membership Revoked Removed 10+ Year Member Joined Dec 1, 2011 Messages 18,577 Reaction score 57 Feb 28, 2012 #1 Members do not see this ad. Watching some wikipremed videos and came across this error. I wanted to make sure that what is shown is a hemiketal and ketal and not a hemiacetal and an acetal.
Members do not see this ad. Watching some wikipremed videos and came across this error. I wanted to make sure that what is shown is a hemiketal and ketal and not a hemiacetal and an acetal.
S SaintJude Full Member 10+ Year Member Joined Jan 4, 2012 Messages 1,479 Reaction score 5 Feb 28, 2012 #2 Yeah, as it's shown, you're right. A hemiketal has 2 R groups. Whereas, a hemiacetal replaces an H for the R. But he might be right if he explicitly said that one of the "R" groups should be assumed to be an H in his lesson. Upvote 0 Downvote
Yeah, as it's shown, you're right. A hemiketal has 2 R groups. Whereas, a hemiacetal replaces an H for the R. But he might be right if he explicitly said that one of the "R" groups should be assumed to be an H in his lesson.
MedPR Membership Revoked Removed 10+ Year Member Joined Dec 1, 2011 Messages 18,577 Reaction score 57 Feb 28, 2012 #3 SaintJude said: Yeah, as it's shown, you're right. A hemiketal has 2 R groups. Whereas, a hemiacetal replaces an H for the R. But he might be right if he explicitly said that one of the "R" groups should be assumed to be an H in his lesson. Click to expand... Yea, I guess so. The process is exactly the same anyway, right? The original H from the aldehyde is never lost in the process. Upvote 0 Downvote
SaintJude said: Yeah, as it's shown, you're right. A hemiketal has 2 R groups. Whereas, a hemiacetal replaces an H for the R. But he might be right if he explicitly said that one of the "R" groups should be assumed to be an H in his lesson. Click to expand... Yea, I guess so. The process is exactly the same anyway, right? The original H from the aldehyde is never lost in the process.