achiever test 3 #71 ochem

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datmachine

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Can someone explain to me how they got answer choice E as the answer. At first I thought the answer would be C. Why is CH3CH3 and -OC(CH3)3 in abundance and why are they denoted as the weaker acid and weaker base. It was also not apparent to me that -OCH2CH3 is a grignard reagent, making it the the 'stronger' base in comparison to -OC(CH3)3.
 
Can someone explain to me how they got answer choice E as the answer. At first I thought the answer would be C. Why is CH3CH3 and -OC(CH3)3 in abundance and why are they denoted as the weaker acid and weaker base. It was also not apparent to me that -OCH2CH3 is a grignard reagent, making it the the 'stronger' base in comparison to -OC(CH3)3.
 
Can someone explain to me how they got answer choice E as the answer. At first I thought the answer would be C. Why is CH3CH3 and -OC(CH3)3 in abundance and why are they denoted as the weaker acid and weaker base. It was also not apparent to me that -OCH2CH3 is a grignard reagent, making it the the 'stronger' base in comparison to -OC(CH3)3.

I think what Achiever is trying to tell is that -OC(CH3)3, an alkoxide, is a strong base by nature. But, when you compare that to a carbanion, H3CH2C:-, it becomes a weaker base comparatively. And carbanion usually comes in the form of Grignard reagent, if I still remember it right. Hope my inputs here help somehow.
 
Which statement CORRECTLY explains the following acid-base reaction at equilibrium? CH3H2C:- + HOC(CH3)3 D CH3CH3 + -:Ö:C(CH3)3

A. Weaker acid, HOC(CH3)3, and weaker base, CH3H2C:-, will be present in abundance. B. Stronger acid, HOC(CH3)3, and stronger base, CH3H2C:-, will be present in abundance.
C.
Weaker acid, CH3CH3, and stronger base, -:Ö:C(CH3)3, will be present in abundance. D. Stronger acid, CH3CH3, and weaker base, -:Ö:C(CH3)3, will be present in abundance. E. Weaker acid, CH3CH3, and weaker base, -:Ö:C(CH3)3, will be present in abundance.
 
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