achiever test 3 chem question

[chyuk84]

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Which statement CORRECTLY explains the following acid-base reaction at equilibrium?
CH3H2C:- + HOC(CH3)3 D CH3CH3 + -:Ö:C(CH3)3

A.Weaker acid, HOC(CH3)3, and weaker base, CH3H2C:-, will be present in abundance.
B.Stronger acid, HOC(CH3)3, and stronger base, CH3H2C:-, will be present in abundance
C.Weaker acid, CH3CH3, and stronger base, -:Ö:C(CH3)3, will be present in abundance.
D.Stronger acid, CH3CH3, and weaker base, -:Ö:C(CH3)3, will be present in abundance.
E.Weaker acid, CH3CH3, and weaker base, -:Ö:C(CH3)3, will be present in abundance.
The answeer is E!!! 😕
can someone explain this for me please? I read the solution, but still cannnot understand it very well.

 

[TeamGuo]

Which statement CORRECTLY explains the following acid-base reaction at equilibrium?
CH3H2C:- + HOC(CH3)3 D CH3CH3 + -:Ö:C(CH3)3

A.Weaker acid, HOC(CH3)3, and weaker base, CH3H2C:-, will be present in abundance.
B.Stronger acid, HOC(CH3)3, and stronger base, CH3H2C:-, will be present in abundance
C.Weaker acid, CH3CH3, and stronger base, -:Ö:C(CH3)3, will be present in abundance.
D.Stronger acid, CH3CH3, and weaker base, -:Ö:C(CH3)3, will be present in abundance.
E.Weaker acid, CH3CH3, and weaker base, -:Ö:C(CH3)3, will be present in abundance.
The answeer is E!!! 😕
can someone explain this for me please? I read the solution, but still cannnot understand it very well.

Since CH3CH2- is a very strong base compared to the other base, it will keep protonating itself to go to the right side, hence the equilibrium favors the right side.

This is just acid/base seeing which acid base is favored due to strength.

 

[klutzy1987]

Well CH3CH3 is not really an acid at all so therefore it is going to be a very very very weak acid. However it is very stable therefore the reaction will favor the formation of it. CH3CH2- is a very unstable powerful base and therfore is not going ot exist much at equilibrium. T-butoxide is still a strong base but nowheer near as strong as CH3CH2-. Therefore it will stay as T-butoxide. This being said the equilibrium then favors the weaker acid (CH3CH3) and the weaker base (-OC(CH3)3).