D
deleted388502
Hi!
I was wondering if someone could conceptually explain dilution to me in the context of a buffer and not in a buffer.
In doing problems in EK, such as problem 837 (a buffer is made by combining 30mL of a 2.0 M acidic soln, the resulting soln has a pH of 7.5, if the soln is then diluted to a total volume of 300mL, what will the new value of the pH - answer was 7.5) - the explanation was that diluting a buffer does not change the pH because the point of a buffer is to resist large changes in pH. This makes sense to me, great.
Now, thinking about diluting a regular solution with water, I get really confused. I know we use henderson-hasselbach to calculate pH for conjugate pairs, but can we use it to account for dilution at all or do we use the M1V1=M2V2 equation?
acids and bases confuse me an incredible amount and if someone could clear up a) how to calculate how dilution effects pH and b) When we would use M1V1=M2V2 to account for dilution, I would really appreciate it!
Thanks!
I was wondering if someone could conceptually explain dilution to me in the context of a buffer and not in a buffer.
In doing problems in EK, such as problem 837 (a buffer is made by combining 30mL of a 2.0 M acidic soln, the resulting soln has a pH of 7.5, if the soln is then diluted to a total volume of 300mL, what will the new value of the pH - answer was 7.5) - the explanation was that diluting a buffer does not change the pH because the point of a buffer is to resist large changes in pH. This makes sense to me, great.
Now, thinking about diluting a regular solution with water, I get really confused. I know we use henderson-hasselbach to calculate pH for conjugate pairs, but can we use it to account for dilution at all or do we use the M1V1=M2V2 equation?
acids and bases confuse me an incredible amount and if someone could clear up a) how to calculate how dilution effects pH and b) When we would use M1V1=M2V2 to account for dilution, I would really appreciate it!
Thanks!