ADA problem 2009 Gen chem

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sexysummer

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What percent of the initial radioactivity will remain after one hour has passed if the half-life of a radioactive isotope is 20 minutes?

This is from the ADA 2009 practice test. I am really rusty on radioactivity problem and do not know how to set them up? Please help me.
 
The half-life is 20 minutes, so one hour is 3 half-lives. Initially you have 100% of the sample, after 3 half-lives, you will go from 100 to 50 to 25 to 12.5%. Thus 12.5% of the initial sample remains.
 
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The half-life is 20 minutes, so one hour is 3 half-lives. Initially you have 100% of the sample, after 3 half-lives, you will go from 100 to 50 to 25 to 12.5%. Thus 12.5% of the initial sample remains.
OK, thanks for replying.

another Question.

dat ada.PNG


Why is it choice B? Is ideal gas @ STP 0 Celsius and 1 atm?

Thanks
 
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OK, thanks for replying.

another Question.

View attachment 196550

Why is it choice B? Is ideal gas @ STP 0 Celsius and 1 atm?

Thanks
Yes, STP is 0 Celcius and 1atm. The problem however does not say anything about STP, only the volume of the ideal gas is zero. You cannot assume that it is STP for any ideal gas. For ideal gas PV = nRT here. You see that if V is 0, then T has to be 0 KELVIN, or -273C.
 
The half-life is 20 minutes, so one hour is 3 half-lives. Initially you have 100% of the sample, after 3 half-lives, you will go from 100 to 50 to 25 to 12.5%. Thus 12.5% of the initial sample remains.
Hello,
Thanks. I sent you another question from gen Chem. Could you assist me with those if possible?

Thank you sir.
 
Yes, STP is 0 Celcius and 1atm. The problem however does not say anything about STP, only the volume of the ideal gas is zero. You cannot assume that it is STP for any ideal gas. For ideal gas PV = nRT here. You see that if V is 0, then T has to be 0 KELVIN, or -273C.
Thank you so much. What about the radioactivity Problem under the first problem?
 
Yes, STP is 0 Celcius and 1atm. The problem however does not say anything about STP, only the volume of the ideal gas is zero. You cannot assume that it is STP for any ideal gas. For ideal gas PV = nRT here. You see that if V is 0, then T has to be 0 KELVIN, or -273C.
Hi,
I want to send you a private message on sdn? How?
 
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