- Joined
- Dec 27, 2007
- Messages
- 710
- Reaction score
- 96
Every amino acid has an isoelectric point (PI) where the carboxy end is deprotonated (COO-) and the amine end is protonated (NH3+), resulting in a net neutral charge.
If the amino acid is in a solution where the PH is above the isoelectric point, than both ends of the amino acid will be in the protonated form (net charge +1), whereas if the PH is below isoelectric point, both ends will be in deprotonated form and thus net charge of -1.
Now how do we relate this to the 2 pKa values of the amino acid? We know the carboxyl end has a pKa that is considerably lower than the pKa at the amine end (since the amine end is basic and the carboxyl end is acidic). If we are in PH solution lower than the carboxyl end's pKa, then that means the carboxyl end is deprotonated and also the amine end is deprotonated as well. If we are at a PH above the pka of the amine end, then the amine end will be protonated (and obviously the carboxyl end will be protonated as well) giving the amino acid a net charge of +1. What about if you are between the 2 pKa's? Is that where the isoelectric point is? If you are at a PH above the pKa of the carboxyl end but lower then the pKa of the amine end, the carboxyl end will be protonated and the amine end will be deprotonated, which gives it a net charge of '0', but this is not the isoelectric state...
I am CONFUSED! Where is isoelectric point relative to the two pKa's?
If the amino acid is in a solution where the PH is above the isoelectric point, than both ends of the amino acid will be in the protonated form (net charge +1), whereas if the PH is below isoelectric point, both ends will be in deprotonated form and thus net charge of -1.
Now how do we relate this to the 2 pKa values of the amino acid? We know the carboxyl end has a pKa that is considerably lower than the pKa at the amine end (since the amine end is basic and the carboxyl end is acidic). If we are in PH solution lower than the carboxyl end's pKa, then that means the carboxyl end is deprotonated and also the amine end is deprotonated as well. If we are at a PH above the pka of the amine end, then the amine end will be protonated (and obviously the carboxyl end will be protonated as well) giving the amino acid a net charge of +1. What about if you are between the 2 pKa's? Is that where the isoelectric point is? If you are at a PH above the pKa of the carboxyl end but lower then the pKa of the amine end, the carboxyl end will be protonated and the amine end will be deprotonated, which gives it a net charge of '0', but this is not the isoelectric state...
I am CONFUSED! Where is isoelectric point relative to the two pKa's?