Another math question...

[HowAboutDAT]

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The endpoints of the diagonal of a square are located at (2,4) and (6,2). Find the area of the square. The answer provided is 10, but I'm not sure thats right, so I wondering what you guys think.

also...

Given that sec x = - 7^1/2 (negative radical 7). Find the value of cos^2 x. Thanks

 

[lazybummy]

I'll do the first one.. i hate trigs.. so i can't help u on the second one lol..

uh.. so use distance formula.. and u'll get sq root of (2-6)^2 + (4-2)^2 which gets u sq root of 20. Since this is the diagonal of the square.. it suggest that each side of the square is sq root of 20 / sq root of 2. To find the area .. u do sq root 20/sq root 2 x sq root 2/sq root 2 = 20/2 = 10!

 

[pbure9]

if sec x = - (radical 7),
then 1/cosx = -(radical 7)
furthermore, cosx will equal -1/(radical 7), which equals -(radical 7)/7

now square that to find cos^2(x) and you get 1/7. =D

Hope that helps

 

[HowAboutDAT]

if sec x = - (radical 7),
then 1/cosx = -(radical 7)
furthermore, cosx will equal -1/(radical 7), which equals -(radical 7)/7

now square that to find cos^2(x) and you get 1/7. =D

Hope that helps

thanks, but apparently the correct answer is 4 radical 3

 

[pbure9]

thanks, but apparently the correct answer is 4 radical 3

where did you get this from? I'm guessing Math Destroyer. Mine says that its 1/7 lol

 

[HowAboutDAT]

where did you get this from? I'm guessing Math Destroyer. Mine says that its 1/7 lol

oh okay fair enough then, thanks for your help