andafoo Andy 15+ Year Member Joined May 1, 2008 Messages 109 Reaction score 2 Points 4,551 Location Earth MD/PhD Student Aug 24, 2008 #1 Advertisement - Members don't see this ad Does anyone know where the equation: KEavg = (3/2)RT For the average kinetic energy of a fluid? Derivations anyone ... if simple?
Advertisement - Members don't see this ad Does anyone know where the equation: KEavg = (3/2)RT For the average kinetic energy of a fluid? Derivations anyone ... if simple?
HawkeyePostOp the fort at sidewalk 10+ Year Member 5+ Year Member 15+ Year Member Joined Jun 4, 2008 Messages 729 Reaction score 0 Points 0 Age 41 Location a long and winding road Aug 24, 2008 #2 if u is root mean square speed of the fluid with molar mass M, Avagadro's number N, then KE is(M/2N)u^2 = 3RT/2N remove N and you have the average ke of a particle = (3/2)RT It's a waste of time unless you're already scoring 13 on PS Upvote 0 Downvote
if u is root mean square speed of the fluid with molar mass M, Avagadro's number N, then KE is(M/2N)u^2 = 3RT/2N remove N and you have the average ke of a particle = (3/2)RT It's a waste of time unless you're already scoring 13 on PS
andafoo Andy 15+ Year Member Joined May 1, 2008 Messages 109 Reaction score 2 Points 4,551 Location Earth MD/PhD Student Aug 24, 2008 #3 HawkeyePostOp said: if u is root mean square speed of the fluid with molar mass M, Avagadro's number N, then KE is(M/2N)u^2 = 3RT/2N remove N and you have the average ke of a particle = (3/2)RT It's a waste of time unless you're already scoring 13 on PS Click to expand... Thanks, I know it rarely shows up, but I didn't want to memorize the equation ... got enough on the brain. Although the derivation does not make sense to me at this point. you are replacing v with the RMS velocity (average velocity) you are also replacing the 'm' with M/N, which is the mass per particle... how does that result in the gas constant and temperature? It looks like it's really close, but I just don't see that 1 intermediate step. Upvote 0 Downvote
HawkeyePostOp said: if u is root mean square speed of the fluid with molar mass M, Avagadro's number N, then KE is(M/2N)u^2 = 3RT/2N remove N and you have the average ke of a particle = (3/2)RT It's a waste of time unless you're already scoring 13 on PS Click to expand... Thanks, I know it rarely shows up, but I didn't want to memorize the equation ... got enough on the brain. Although the derivation does not make sense to me at this point. you are replacing v with the RMS velocity (average velocity) you are also replacing the 'm' with M/N, which is the mass per particle... how does that result in the gas constant and temperature? It looks like it's really close, but I just don't see that 1 intermediate step.
HawkeyePostOp the fort at sidewalk 10+ Year Member 5+ Year Member 15+ Year Member Joined Jun 4, 2008 Messages 729 Reaction score 0 Points 0 Age 41 Location a long and winding road Aug 24, 2008 #4 u = (3kNT/M)^(1/2) Upvote 0 Downvote