Biology question kaplan workshopA #29-help needed!

[phosphatase]

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Biology question kaplan workshopA #29-help needed! Thanks!



29. Laboratory mice are to be classified based on genes A,
B, and C. How many genetically distinct offspring can
be produced from a cross of an AaBbCc individual with
an AaBBCc individual?

A. 12
B. 16
C. 32
D. 48
E. 64

Kaplan answer (which I think is wrong): 29. C
The number of genetically distinct offspring is found by multiplying number of distinct gametes each parent
can produce. The number of gametes can be calculated from the formula 2n, where n = the number of
heterozygous genes. The AaBbCc parent can produce 8 unique gametes (23=8) and the AaBBCc parent can
produce 4 (22=4). Therefore the possible number of different offspring is 8 x 4 = 32.

My solution: {AA Aa aa} * {BB Bb} * {CC Cc cc}=3*2*3=18

 

[americanpierg]

Biology question kaplan workshopA #29-help needed! Thanks!



29. Laboratory mice are to be classified based on genes A,
B, and C. How many genetically distinct offspring can
be produced from a cross of an AaBbCc individual with
an AaBBCc individual?

A. 12
B. 16
C. 32
D. 48
E. 64

Kaplan answer (which I think is wrong): 29. C
The number of genetically distinct offspring is found by multiplying number of distinct gametes each parent
can produce. The number of gametes can be calculated from the formula 2n, where n = the number of
heterozygous genes. The AaBbCc parent can produce 8 unique gametes (23=8) and the AaBBCc parent can
produce 4 (22=4). Therefore the possible number of different offspring is 8 x 4 = 32.

My solution: {AA Aa aa} * {BB Bb} * {CC Cc cc}=3*2*3=18

Kaplan is correct, and your solution is incorrect becuase your reasoning is incorrect. Aa is not the same as aA because they come from a different parent. Think of what would happen if you crossed AaBbCc with AaBbCc with your method.

 

[phosphatase]

if I crossed AaBbCc with AaBbCc with my method {AA Aa aa} * {BB Bb bb} * {CC Cc cc}=3*3*3=27

----Aa is not the same as aA because they come from a different parent.---
Why? can you explain more? thank you! what's the difference if they are same allele?

 

[wantVCUdental]

Kaplan is correct, because in the first one there are 8 possible genotypes and in the second one there are 4 possible genotypes, when you cross them you get 32

 

[phosphatase]

These are the only 18 possible offsprings I can think of. Could you please just name another one if you think there are 32 totally? thanks

AABBCC
AaBBCC
aaBBCC
AABbCC
AaBbCC
aaBbCC
AABBCc
AaBBCc
aaBBCc
AABbCc
AaBbCc
aaBbCc
AABBcc
AaBBcc
aaBBcc
AABbcc
AaBbcc
aaBbcc

 

[americanpierg]

if I crossed AaBbCc with AaBbCc with my method {AA Aa aa} * {BB Bb bb} * {CC Cc cc}=3*3*3=27

----Aa is not the same as aA because they come from a different parent.---
Why? can you explain more? thank you! what's the difference if they are same allele?

AaBbCc x AaBbCc = 64

If each parent had the genotype Aa, they can contribute both an "A" and an "a." Aa where A= father's and a=mother's is not the same as A= mother's and a=father's.

 

[phosphatase]

thanks Americanpierg.

So you are saying a "father A" is different from a "mother A". Could you please tell me what's the difference? Are their sequences different? then why they have same symbol?

Also in that case, a mundel bean cross of Aa *Aa would produce 4 different offsprings (1:1:1:1) in your opinion?

thanks

 

[phosphatase]

Anyone please?

 

[wantVCUdental]

I don't think you should dwell on this, because it's a really bad question and the answer is really up for discussion because you can answer it depending on the way you interpret the Q.
Anyway,
Aa x Aa would give you 4 distinct in this case.

 

[americanpierg]

Anyone please?

I think you're right. Theres 8 distinct gametes on one side and 4 on the other, but crossing them produces a lot of redundency (ie AABBCc vs AABBcC). I guess the answer SHOULD be 18. But if you think deeper into this, a boy and a girl would be genetically distinct too, so wouldn't it be 36 then?

 

[lakers2009]

Result from software generated export

 

[lakers2009]

if I crossed AaBbCc with AaBbCc with my method {AA Aa aa} * {BB Bb bb} * {CC Cc cc}=3*3*3=27

----Aa is not the same as aA because they come from a different parent.---
Why? can you explain more? thank you! what's the difference if they are same allele?

So your way is good phosphatase (anti-kinase, dephosphorylase, dephosphotransferase)

 

[phosphatase]

haha ,thanks guys!