- Joined
- May 13, 2011
- Messages
- 11
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The question asks the following: "What is the mass ratio of iron to oxygen in Fe2O3?"
For my work I multiplied 2(55.85) and 3(16). I rounded to get a ratio of 112:48. I then said that this ratio is approximately 114:50 so I could arrive at 228:100. This gets me very close to the correct answer of 2.33 g with the next closest answer choices being 1.63 g and 3.49 g.
In the explanation they kept it 111.7:48.0 which is fine but they state that this ratio is approximately equal to 116:50. The book states that both must be increased proportionally to keep the ratio the same. I understand that they are both about 2.32 but how would you know what numbers to change it to so that the ratio stays the same? I just thought a little bit on top and a little bit on bottom.
I did get the correct answer but there have been times where I have rounded and got the answer wrong. EK says that the answers will not be close enough and the mistake must be mine. I am trying to develop elimination tactics because I think it is a major factor for the MCAT score that I want.
For my work I multiplied 2(55.85) and 3(16). I rounded to get a ratio of 112:48. I then said that this ratio is approximately 114:50 so I could arrive at 228:100. This gets me very close to the correct answer of 2.33 g with the next closest answer choices being 1.63 g and 3.49 g.
In the explanation they kept it 111.7:48.0 which is fine but they state that this ratio is approximately equal to 116:50. The book states that both must be increased proportionally to keep the ratio the same. I understand that they are both about 2.32 but how would you know what numbers to change it to so that the ratio stays the same? I just thought a little bit on top and a little bit on bottom.
I did get the correct answer but there have been times where I have rounded and got the answer wrong. EK says that the answers will not be close enough and the mistake must be mine. I am trying to develop elimination tactics because I think it is a major factor for the MCAT score that I want.