Chemistry problem

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ef1553

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The resulting solution made from the combination of 50ml of 1.0M LiOH with 50ml of 1.0M HBr will be identical in all respects to 100ml of


.5M
1.0M
2.0M

Thought it would be 1.0 but its .5. Explain?
 
I could be wrong but I thought I'd give it a shot. When you look at the formula for Molarity it is M= number of mols/ volume

In the problem you are essentially doubling the volume which would decrease the molarity by half, assuming you kept the same number of mols for each.
 
I could be wrong but I thought I'd give it a shot. When you look at the formula for Molarity it is M= number of mols/ volume

In the problem you are essentially doubling the volume which would decrease the molarity by half, assuming you kept the same number of mols for each.

This sounds about right.

1.0M substance A in 50mL solution = 0.5M of substance A if another 50mL was added (100mL total).
 
on a similar note to using that formula, you get # of moles by multiplying the numbers for each species and the moles has to be constant in each at 0.05 moles. (1M)(0.05L) = 0.05 mole, so the same calculation in all of them pretty much.
 
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