chemistry SPECATOR ions

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

arpitpatel86

Full Member
10+ Year Member
15+ Year Member
Joined
May 9, 2008
Messages
104
Reaction score
0
how do u know what the spectator ion are...like i know what they are and can identify them in solving net ionic equations but.... when they give u a questions like...

WHICH SALT WILL FORM A SOLUTION WITH A pH LESS THAN 7?

A. KBr
B. NH4NO3
c. NaF
d. KCN
e. Na2CO3

it says remove the spectator ions first which includes K,Br,NO3, F, Na ....how do we know that they are spectator ions?
 
how do u know what the spectator ion are...like i know what they are and can identify them in solving net ionic equations but.... when they give u a questions like...

WHICH SALT WILL FORM A SOLUTION WITH A pH LESS THAN 7?

A. KBr
B. NH4NO3
c. NaF
d. KCN
e. Na2CO3

it says remove the spectator ions first which includes K,Br,NO3, F, Na ....how do we know that they are spectator ions?

The term spectator ion should be used only when talking about reactions. All of the answer choices are ionic compounds, so to get the answer, just look at all the separate ions. All the anions (Br-, NO3-, F-, CN-, CO3 2-) are bases, so they're out. Na+ and K+ are happy as cations, so they're also out. So the only one left is NH4+, which is a weak acid and forms an acidic solution.
 
Hi Arpitpatel86. I understand your question about spectator ions, and yes, they are at times difficult to notice, but its doable. =) Let's take a look and take it one step at a time.

First, what are spectator ions?
Spectator ions are atoms (charged) that do not participate in the reaction. That means they will appear in both the reactants and products, and will not participate in the chemical reaction. For example, think of it like us! When we volunteer at dental offices, we are not participating in the actual procedure to be performed on the patient - we are spectators. Even though we may help out, we are not directly participating in the procedure. We are spectators like the crowd at the Lakers game.

How do you know which are spectator ions?
In order to understand this aspect, and the answer to your question, you need to be aware of solubility rules. As the name implies, it pertains to the appearance of a precipitate at the completion of the reaction. You can find solubility rules in the KAPLAN book, or any chem book would suffice.

Now lets take your choices one at a time:

KBr
"Salts containing Group I elements are soluble (Li+, Na+, K+, Cs+, Rb+).Salts containing Cl -, Br -, I - are generally soluble. " - This is the definition straight from my book.

NaF
If we look in the second line of the quote above, we see that F is not one of the choices. Therefore, F would participate in the reaction, but how?
F + H2O --> HF + OH-
Please follow this technique for choices C to E, and lets get to the answer. Great!

"Salts containing nitrate ion (NO3-) are generally soluble."

Which means we only have NH4+ left. This species will donate its proton to water forming H3O+, and hence the solution would be acidic (power of Hydrogen (pH) less than 7).

I'll check later on to see if you are still unclear.
 
thanks a lot for the explanation....lets see if i understand this so if something is watersoluble it it is a spectator ion? and if that is the case isnt NH+ soluble
 
how do u know what the spectator ion are...like i know what they are and can identify them in solving net ionic equations but.... when they give u a questions like...

WHICH SALT WILL FORM A SOLUTION WITH A pH LESS THAN 7?

A. KBr
B. NH4NO3
c. NaF
d. KCN
e. Na2CO3

it says remove the spectator ions first which includes K,Br,NO3, F, Na ....how do we know that they are spectator ions?

This particular question is made much easier if you know that NH4 is a very common weak acid; some of the other ions are common conjugate bases but that's it. Still, it's probably a good idea to understand the concept of spectator ions for those other questions that ask about net ionic equations.
 
Hi. Yes you are correct that NH4+ is water soluble, but I also agree with La brat, in that it will donate its H+. NH4+ is acting as Lowry Acid and will simply donate its proton to water making the solution acidic.

I know that the reasoning behind this question seems to contradict itself from one point to another, but I believe when it comes to spectator ions, you have to get a feel to it, which comes with doing numerous calculations and equations. It comes with practice. As you practice through equations and setting up balanced formulas, you will get a feel for what the players in a reaction. Hope this helps. Try working through other reactions from DAT Destroyer, where I believe your question is coming from. There should be other problems that address this concept.
 
Ammonium nitrate is a salt of a weak base and a strong acid and, as expected, a solution would be acidic.
Sodium carbonate is a salt of a strong base and a weak acid and a solution would be basic.
 
Top