common ion effect problem

[twenty7]

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I understand common ion effect but what if they ask you to solve for the volume instead of molarity? I have an example:

BaSO4 (s) <-> Ba2+ + SO42- Ksp = 1.1 x -10

What volume of 1M BaSO4 solution must be added to 1L of a 0.01M BaCl2 solution to begin precipitation?

Solving for x without common ion:

Ksp = [Ba] [SO4] (left out charges for simplicity's sake)
1.1 x -10 = (x)(x)

Solving for x with common ion:

1.1 x -10 = (x + 0.01)(x) = 0.01(x)

x = 1.1 x 10^-8 M = [SO4]

Now how do I find the volume of the 1 M BaSO4 solution?

 

[MedPR]

I understand common ion effect but what if they ask you to solve for the volume instead of molarity? I have an example:

BaSO4 (s) <-> Ba2+ + SO42- Ksp = 1.1 x -10

What volume of 1M BaSO4 solution must be added to 1L of a 0.01M BaCl2 solution to begin precipitation?

Solving for x without common ion:

Ksp = [Ba] [SO4] (left out charges for simplicity's sake)
1.1 x -10 = (x)(x)

Solving for x with common ion:

1.1 x -10 = (x + 0.01)(x) = 0.01(x)

x = 1.1 x 10^-8 M = [SO4]

Now how do I find the volume of the 1 M BaSO4 solution?

Why wouldn't it be .01L BaSO4?