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11. What is the mass percent of methanol in a solution prepared by diluting 16 grams of methanol with 32 grams of water?
The answer says mass percent = g of solute/g of solution which is 16/48 x100 but I thought mass percent/percent composistion was an intrinsic factor, and you only calculate it with the mass of the element/mass of the compound which would be CH4= 16 H2O =18
so grams CH4/G CH4 + H2O = 16g/34g x 100 = about ... 50% Why am I wrong?
The answer says mass percent = g of solute/g of solution which is 16/48 x100 but I thought mass percent/percent composistion was an intrinsic factor, and you only calculate it with the mass of the element/mass of the compound which would be CH4= 16 H2O =18
so grams CH4/G CH4 + H2O = 16g/34g x 100 = about ... 50% Why am I wrong?