DAT destroyer GC question

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Veni vidi vicii

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NH2OH has a kb of 1.1x10^-8. What represents the dissociation equation? the answer was NH2OH + H20 <---> NH3(+)OH + OH-.

Can an alternative answer be NH2OH + H20 <---> NH(-)OH + H3O+. Since water has kb value of 1x10^-7, it would be the stronger base and deprotonate. Or am I thinking of this wrong? In the answer it says since kb was given you know it's a base so hydroxide ions need to be produced.
 
No, precisely because Kb of H20 is greater (10x) than Kb of NH2OH, so that H20 can only act as conjugate acid against more basic NH2OH.
I thought a higher Kb meant more basic, similar to a low pKb, so I would think water would 10x more basic?
 
I thought a higher Kb meant more basic, similar to a low pKb, so I would think water would 10x more basic?

Using Bronsted-Lowry definition, acid H20 donates H+, base NH2OH accepts H+.
Using Arrhenius definition, amphoteric H20 produces both H+ and OH-.
 
Using Bronsted-Lowry definition, acid H20 donates H+, base NH2OH accepts H+.
Using Arrhenius definition, amphoteric H20 produces both H+ and OH-.
That's nice and all but that just brings us back to what I originally asked. Why is water acting as an acid when it's 10x more basic than NH2OH?
 
That's nice and all but that just brings us back to what I originally asked. Why is water acting as an acid when it's 10x more basic than NH2OH?

Because it just happens that H2O is an amphoteric compound that also produces OH-, not just H+ (equal amount at pH=7). If NH2OH reacts with H2S that carries H+ but not OH-, for example, resulting pH would be lower due to the lack of OH-, though stronger acid H2S still donates its H+ to NH2OH.

NH2OH + H2S <-> NH3 • H2O + S
 
Because it just happens that H2O is an amphoteric compound that also produces OH-, not just H+ (equal amount at pH=7). If NH2OH reacts with H2S that carries H+ but not OH-, for example, resulting pH would be lower due to the lack of OH-, though stronger acid H2S still donates its H+ to NH2OH.

NH2OH + H2S <-> NH3 • H2O + S
Gotcha
 
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