H hell0k1tty Full Member 10+ Year Member Joined May 4, 2010 Messages 83 Reaction score 0 Jul 28, 2010 #1 Members do not see this ad. Why does the 2-bromo-butane turn into 1-butene when reacted with (CH3)3CO-K+ instead of becoming 2-butene? Is it because (CH3)3CO-K+ is bulky? 😕
Members do not see this ad. Why does the 2-bromo-butane turn into 1-butene when reacted with (CH3)3CO-K+ instead of becoming 2-butene? Is it because (CH3)3CO-K+ is bulky? 😕
D DQLEUCD Full Member 10+ Year Member Joined Jun 30, 2010 Messages 271 Reaction score 0 Jul 28, 2010 #2 hell0k1tty said: Why does the 2-bromo-butane turn into 1-butene when reacted with (CH3)3CO-K+ instead of becoming 2-butene? Is it because (CH3)3CO-K+ is bulky? 😕 Click to expand... It should form the 2-butene. Where is this question at? Upvote 0 Downvote
hell0k1tty said: Why does the 2-bromo-butane turn into 1-butene when reacted with (CH3)3CO-K+ instead of becoming 2-butene? Is it because (CH3)3CO-K+ is bulky? 😕 Click to expand... It should form the 2-butene. Where is this question at?
P PreDental88 Full Member 10+ Year Member Joined Dec 28, 2008 Messages 84 Reaction score 0 Jul 28, 2010 #3 hell0k1tty said: Why does the 2-bromo-butane turn into 1-butene when reacted with (CH3)3CO-K+ instead of becoming 2-butene? Is it because (CH3)3CO-K+ is bulky? 😕 Click to expand... It's because this base is very bulky and forming the 2-butene would be less favorable due to steric hindrance in the base. LDA also behaves similarly Upvote 0 Downvote
hell0k1tty said: Why does the 2-bromo-butane turn into 1-butene when reacted with (CH3)3CO-K+ instead of becoming 2-butene? Is it because (CH3)3CO-K+ is bulky? 😕 Click to expand... It's because this base is very bulky and forming the 2-butene would be less favorable due to steric hindrance in the base. LDA also behaves similarly
P PreDental88 Full Member 10+ Year Member Joined Dec 28, 2008 Messages 84 Reaction score 0 Jul 28, 2010 #4 A less sterically hindered base such as NaOCH2CH3 will produce 2-butene. When doing E2 problems, it's important to consider what factors influence it's rate: k = [Base][Rx] Hope that helps =) Last edited: Jul 28, 2010 Upvote 0 Downvote
A less sterically hindered base such as NaOCH2CH3 will produce 2-butene. When doing E2 problems, it's important to consider what factors influence it's rate: k = [Base][Rx] Hope that helps =)
H hell0k1tty Full Member 10+ Year Member Joined May 4, 2010 Messages 83 Reaction score 0 Jul 28, 2010 #5 Thanks! Def. helped 🙂 Upvote 0 Downvote
H hell0k1tty Full Member 10+ Year Member Joined May 4, 2010 Messages 83 Reaction score 0 Jul 28, 2010 #6 DQLEUCD said: It should form the 2-butene. Where is this question at? Click to expand... It was a reaction located in Roadmap 5 Upvote 0 Downvote
DQLEUCD said: It should form the 2-butene. Where is this question at? Click to expand... It was a reaction located in Roadmap 5