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- Jul 2, 2014
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Ok guys I understand the theory behind disassociation well. I am just missing a key part in this question, I know that for H2SO4 that only one H+ will fully disassociate and the other partially.Therefore the pH will not be exactly 3. I understand this key point.
Now this next part is what I find tricky, if the second H+ "DID" fully disassociate then the value would be exactly 3. However, if it does not then the value would not be 3, but how is it lower then 3? A value lower then 3 would mean that the solution in more ACIDIC? I would assume since both H's are not disassociating that the value would be more than 3 since the solution would be less ACIDIC with less number of H's freely roaming the solution? I do not like to memorize rather understand this. Thanks
I attached the problem to this message below!
Now this next part is what I find tricky, if the second H+ "DID" fully disassociate then the value would be exactly 3. However, if it does not then the value would not be 3, but how is it lower then 3? A value lower then 3 would mean that the solution in more ACIDIC? I would assume since both H's are not disassociating that the value would be more than 3 since the solution would be less ACIDIC with less number of H's freely roaming the solution? I do not like to memorize rather understand this. Thanks
I attached the problem to this message below!