N nona Full Member 10+ Year Member Joined Jul 10, 2009 Messages 57 Reaction score 0 Jun 25, 2010 #1 Members don't see this ad. can someone please explain to me how to solve Q38 Test 9 in DAT math destroyer I would really appreciate it because the answer is not explained with the answers for some reason they explained Q40 instead🙁
Members don't see this ad. can someone please explain to me how to solve Q38 Test 9 in DAT math destroyer I would really appreciate it because the answer is not explained with the answers for some reason they explained Q40 instead🙁
S silveryhair Full Member 10+ Year Member 5+ Year Member 15+ Year Member Joined Jul 23, 2008 Messages 249 Reaction score 0 Jun 25, 2010 #2 I havent got there, but I looked at the problem and the answer should be 1/2. Let me know if u need an explanation. It follows the Log division rule Log x - log y = log x/y Destroyer has the answer as D, but it the correct answer is A. If you don't believe me, plug it into a calculator 😉 Last edited: Jun 25, 2010 Upvote 0 Downvote
I havent got there, but I looked at the problem and the answer should be 1/2. Let me know if u need an explanation. It follows the Log division rule Log x - log y = log x/y Destroyer has the answer as D, but it the correct answer is A. If you don't believe me, plug it into a calculator 😉
N NewBee12 Full Member 10+ Year Member Joined Jan 11, 2010 Messages 380 Reaction score 15 Jun 26, 2010 #3 Log(28) - Log(7x) = Log(8) Log(28/7x) = Log(8) which means : 28/7x = 8 now solve for x x= 28/56 = 1/2 😀 good luck Upvote 0 Downvote
Log(28) - Log(7x) = Log(8) Log(28/7x) = Log(8) which means : 28/7x = 8 now solve for x x= 28/56 = 1/2 😀 good luck
N nona Full Member 10+ Year Member Joined Jul 10, 2009 Messages 57 Reaction score 0 Jun 26, 2010 #4 thanks newbee12 and silveryhair Upvote 0 Downvote