Determine the numerical value of the rate constant for the reaction A+B⟶C from the experimental data given below.
Experiment [A] Rate
1 0.43 M 0.21 M 1.52 M/s
2 0.43 M 0.44 M 6.06 M/s
3 0.87 M 0.21 M 3.05 M/s
A:k=(0.45)(0.21)1.52
B: k=1.52(0.43)(0.21)2
C: k=(0.43)(0.21)21.52
D: k=(0.21)21.52
E: k=(0.43)2(0.21)21.52
Explanation
The data in the table shows is the effect of doubling each reactant on the overall rate of reaction. When [A] is doubled, the rate of reaction also doubles. Thus, the reaction is first order with respect to A. When is doubled the rate is quadrupled. Thus the rate is 2nd order in B. The rate constant expression is rate=k[A]2 . If we solve this for k and plug in the values for Rate, [A], and from the first experiment, we get the correct answer. (Note that the values for any of the experiments can be used; the value of k will not differ other than by experimental error)
I think this is an error. A should not even be in the equation. Please help! i am so confused.
Experiment [A] Rate
1 0.43 M 0.21 M 1.52 M/s
2 0.43 M 0.44 M 6.06 M/s
3 0.87 M 0.21 M 3.05 M/s
A:k=(0.45)(0.21)1.52
B: k=1.52(0.43)(0.21)2
C: k=(0.43)(0.21)21.52
D: k=(0.21)21.52
E: k=(0.43)2(0.21)21.52
Explanation
The data in the table shows is the effect of doubling each reactant on the overall rate of reaction. When [A] is doubled, the rate of reaction also doubles. Thus, the reaction is first order with respect to A. When is doubled the rate is quadrupled. Thus the rate is 2nd order in B. The rate constant expression is rate=k[A]2 . If we solve this for k and plug in the values for Rate, [A], and from the first experiment, we get the correct answer. (Note that the values for any of the experiments can be used; the value of k will not differ other than by experimental error)
I think this is an error. A should not even be in the equation. Please help! i am so confused.