Deactivating or not?

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SGStudent

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The answer is +NR3 which I understand because it lacks a lone pair that can make the benzene more nucleophilic and therefore better reaction with electrophiles. But why isn't C with two oxygens attach consider electron withdrawing group? I thought since carbon is attach to more electronegative atom oxygen it becomes partially positive and so will make the benzene less nucleophilic.

If you can help me, I really appreciate it. Have a great holidays!

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I think like this:

you know -OH is active group, -OR also active group.
So, the two -OR acrive the C connect to it.

In one world, if you understand -OCH3 is better active group than -CH3, you will understand it.


Strongly Activating Groups[edit]
  • -NH2
  • -NHR
  • -NR2
  • -OH
  • -O-
R = alkyl

Strongly activating substituents favor electrophilic substitution about the ortho and para positions.
This is illustrated by drawing the resonance structures of aniline: [1]

Moderately Activating Groups[edit]
  • -NHCOCH3
  • -NHCOR
  • -OCH3
  • -OR
Weakly Activating Groups[edit]
  • -CH3
  • -C2H5
  • -R
  • -C6H5
 
If you still do not understand, just forget the weired group. I think the real test unlikely asks such knid of weired group.
 
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