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Haha, I actually had the same question I was thinking about posting today.

You go wrong right in the first step.

delta U = q - w

The only reason it is + w in your equation is because that is work done ON the gas, not work done BY the gas.

I think that should solve your problems.

Or if you want to stay consistant, in your third equation, you are using work done BY the gas. Change this to W = -p delta V, then it would work as well.
 
So,
By the gas
delta U = q - w
w = p*deltaV

On the gas
delta U = q + w
w = - p*deltaV

so in either case,
delta H = q
 

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