destroyer gchem 114

[ldm0208]

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The set of quantum numbers of Na are 3,0,0,1/2 ??? Should be 3,0,1,1/2, right?

searched first but counldn't find it.

 

[Mamona]

I think you're right!!!

 

[Thundercatz]

The set of quantum numbers of Na are 3,0,0,1/2 ??? Should be 3,0,1,1/2, right?

searched first but counldn't find it.

No, since the L = 0, ml can not be 1. Remember that ml is +/- L.

 

[ldm0208]

No, since the L = 0, ml can not be 1. Remember that ml is +/- L.

no, i don't think so. it's +/- L including 0. so, s subshell, where there is one possible value of ml = 0, will contain 1 orbital orientation. The formula for ml is 2L+1. I am like 100% sure but who knows maybe I am completely missing something. Let me know!

 

[Thundercatz]

no, i don't think so. it's +/- L including 0. so, s subshell, where there is one possible value of ml = 0, will contain 1 orbital orientation. The formula for ml is 2L+1. I am like 100% sure but who knows maybe I am completely missing something. Let me know!

Nope. You need to look this up.

The first quantum number is N.

The 2nd quantum number is L, and it can be n-1.

The 3rd quantum number is ml, and it be +/- L.

The valence electron configuration of Na is 3s1.

S implies that it has a 0 subshell (L).

If the subshell is 0, how can the orbital number (ml) be 1? That doesnt make any sense.

 

[ldm0208]

S implies that it has a 0 subshell (L). NONONO

If the subshell is 0, how can the orbital number (ml) be 1? That doesnt make any sense.

the subshells corresponding to L=0,1,2,and 3 ARE KNOWN AS the s,p,d, and f respectively!! so we can use this number to find out ml. That doesn't mean S has a 0 subshell!

Comeon! let's then think about P. P=1 -> the possible values of ml are all integer from -L to +L including 0, so -1,0,+1. Again these numbers don't imply that it has -1 subshell? 0 subshell? or +1 subshell? nonono.. It means P has 3(2L+1=3) dumbbell-shaped orbital orientations, which are Px, Py, and Pz.

So, S=0 means we have 1(2L+1=1) sphere-shaped orbital orientation!

 

[Thundercatz]

the subshells corresponding to L=0,1,2,and 3 ARE KNOWN AS the s,p,d, and f respectively!! so we can use this number to find out ml. That doesn't mean S has a 0 subshell!

Comeon! let's then think about P. P=1 -> the possible values of ml are all integer from -L to +L including 0, so -1,0,+1. Again these numbers don't imply that it has -1 subshell? 0 subshell? or +1 subshell? nonono.. It means P has 3(2L+1=3) dumbbell-shaped orbital orientations, which are Px, Py, and Pz.

So, S=0 means we have 1(2L+1=1) sphere-shaped orbital orientation!

Ok,

I think you need to go back and reference your chemistry book.

SPDF = 0,1,2,3. This means that the S subshell can hold only 2 elections. One with a ml 0 and ms +1/2 and one with 0 -1/2.

So ml is +/- 0.

I am not going to argue this simple problem with you any longer.

And here is a direct quote from my book:

An electron's third quantum number, the orbital number, is denoted my ml. It describes the three-dimensional orientation of an orbital. The possible values of ml depends on L as follows: ml = -L, -(L-1),..... For example, if L = 2, then ml could be -2, -1, 0, 1, 2. If l = 0, then ml can only be equal to 0 (one possibility), so each subshell has just 1 orbital.


Thats DIRECTLY from my text book. Have a nice day.

 

[klutzy1987]

Thundercatz is 100% correct. Ml can never have a greater absolute value than L. The formula as Thundercatz stated is Ml equals from positive to negative L, zero included. You are mistaken ldm.

 

[ldm0208]

Okay..I think I got it. I thought ml=1 because ml=0 means 1 orbital . NOW IT DOESN'T MAKE SENSE!!😀 Yeah it has one orbital, but that's not the ml number. I ended up thinking that in my way there is no way I can differentiate the sets of quantum numbers between Na and Mg.

So, I did some work to make sure I really understood this easy concept, which I though I did like 5years ago..

What are all possible quantum number sets for an electron in the 3rd energy level in the p-subshell?
n = 3 ( principal quantam no)
l = 1 (azimuthal quantam no)
m= -1,0,1 (magnetic quantum no)
s = -1/2,1/2(spin quantam no)

Sets are:
1. Al=(3,1,-1,-1/2)
2. Si=(3,1,-1,1/2)
3. P=(3,1,0,-1/2)
4. S=(3,1,0,1/2)
5. Cl=(3,1,1,-1/2)
6. Ar=(3,1,1,1/2)

Thank you so much! Thundercatz and klutzy1987
especially Thundercatz! Thank you for arguing with me!! You are GREAT 👍