Destroyer Oc #5....

[illbirz]

---

Members don't see this ad.

Can some1 help explain to me the solution. Cause the book sure doesn't help. i have the new Destroyer the 2008 edition.

 

[TheWiredNerv]

I would but I don't have it anymore.

 

[gomawum]

good I just bought the destroyer and got it on my hand today.

1) K2Cr2O7 is good oxidizing agent, so oxidize alcohol to ketone
2) (C6H5)3P=CH2 is a wittig reaction so CH2 is double bonded to where carbonyl carbon was used to be (just replace O with CH2)
3) this is hydroboration, and hydroboration always is anti-markovnikov, and is syn addition



did u get #4?
I was ambugiuous b/t a and b, but I can't see why a is not the answer

 

[illbirz]

Hii gomawum, first let me thank you for your perfect explanation. Man did i waste some time trying to decipher that problem. Anywhoo, thank you. Also WiredNerd, thank u for replying as well. Gomawum as far as #4, you gotta make sure that you attack using the left side of the nitrogen containing compound. What Choice A does, it uses the Nitrogen closest to the double bond O, but in choice B the correct nitrogen is used, the one that is farthest from the double bond oxygen. I believe simply because of the nature of double Bond O that the amine portion is used for a point of attack. i know its a horrible explanation on my behalf, but tell me if u get it...if not ill try a different way. Yea? 👍 or Nay? 👎

p.s. lets not forget amides are N's bonded to a carbonyl group. and Amines are just N's bonded to Hydrogens or regular C atoms.