destroyer OG

[Nano242]

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Hi everyone,
I have a question regarding organic chemistry in destroyer... question # 97..
can any one explain to me how does this reaction work? I am not quite sure about the answer.. please help me!!!

 

[whoaaitzkyle]

Hi everyone,
I have a question regarding organic chemistry in destroyer... question # 97..
can any one explain to me how does this reaction work? I am not quite sure about the answer.. please help me!!!

First off, assume you are saturated in CH3MgCl.

1 mole attacks and the carbonyl turns into O-.

The O- reforms the carbonyl and kicks off the -OCH3 group because that is the most stable form. Now you have a ketone.

Another mole attacks the ketone and the O- is protonated with H30+ resulting in t-butyl alcohol.