Destroyer...

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Dont worry, not here to bash.. just have a simple question...

bio #160. For Hardy-Weinberg equations, isnt q = recessive allele frequency? and if this is so, then im not understanding why it says let q^2 = 1/2500, because isnt q^2 frequency of homozygous recessive, and not the allele? Can someone clarify this for me?

Thanks
 
Dont worry, not here to bash.. just have a simple question...

bio #160. For Hardy-Weinberg equations, isnt q = recessive allele frequency? and if this is so, then im not understanding why it says let q^2 = 1/2500, because isnt q^2 frequency of homozygous recessive, and not the allele? Can someone clarify this for me?

Thanks

The problem says 1/2500 have the recessive trait AMONG WHITE AMERICANS....which means its talking about the frequency within a population. Whenever youre dealing with a trait in a population always use the p2+2pq+q2 formula. If it just said the recessive allele frequency (and didnt mention any population) is 1/2500 then you would use the p+q=1 formula. Hope that helps
 
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