In this question # 13) For molecule A, I have R for the fourth carbon (carbonyl carbon is 1) and S for the 2 carbon (next to carbonyl). Are those correct? There is no stereochemistry for 3'rd carbon since it has 2 methyl groups attached. Right? Is there a quick way to just look at the molecule and get the diastereomer rather than evaluate stereochemistry? Please let me know. Anyways, I thought 1 and 4 are diastereomers, so just wanted to run it by you all. So I think b) is correct ans. Let me know....Thanks!
Diastereomers...
- Thread starter sps27
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I got the same answers as you for chirality of A and B as the answer. If you are only comparing molecules you don't need to resolve the stereochemisty at all. I mentally rotate one molecule so that it overlaps with another molecule. If one of the groups is pointing the wrong direction after aligning the two molecules then it is a diastereomer (unless both chiral groups are the wrong direction, then it is not).
