Dielectrics

[549]

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Hi,

Regarding capacitors and dielectrics, I wanted to clarify if the following makes sense.

If you charge a capacitor, remove the voltage source, and insert a dielectric, then the capacitance will increase (due to the dielectric), the charge will remain the same (due to the lack of voltage supply), and the voltage between the plates will drop.

If you charge a capacitor, leave the voltage source attached, and insert a dielectric, then the capacitance will increase (due to the dielectric), the charge will increase (due to the voltage source supplying charge), and the voltage across the plates will remain the same.

Is that correct, or am I missing something here? In both cases, the dielectric increases the capacitance, right?

Thanks.

 

[Doodl3s]

I second wanting an answer to this, I always screw up dielectrics...

 

[wanderer]

Both are correct.

 

[549]

Alright- thanks!