Difficult Redox Reaction from Practice Test...Need Help!!

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csafizadeh

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The reaction unbalanced reaction is:

KMnO4 + NH3 ---> KNO3 + MnO2 + KOH + H2O

every time I balance it using the half equation method I get:

3(NH3) + 8 (KMnO4) ---> 3 (KNO3) + 8 (MnO2) + 5 (K+) + 7 (OH-) + 4 (H2O)

That is incorrect however,

I am assuming this reaction is being done in basic solution (KOH) so I am adding OH to balance the oxygens and H2O to balance the hydrogens? Any ideas on what I am doing wrong? How do I solve this redox to get the right amount of water and hydroxide molecules?
 
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